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How Do I???

Posted: Thu Jan 21, 2010 6:54 am
by ZiggySlide
:matrix:

How do I go about adding JPG files to a report. the Location of the JPG file is stored in a Database as a link to a network location.

each report has multiple images.

I do not know how to build the report with code - we use the GUI interface

Any assistance is appreciated

Thanks in advance

Ziggy.

How Do I???

Posted: Thu Jan 21, 2010 11:50 am
by Edward
Hi Ziggy,

Please do the following:

Double click the Image component in the Designer.
Click 'Image Data' tab.

Add the following code there:

{Image.FromFile(DataSource.DataColumnWithPathToImage)}

Thank you.

How Do I???

Posted: Wed Jan 27, 2010 8:12 am
by ZiggySlide
Ed,

I tried to figure out what you are meaning, but am not seeing it.

We are using Reports.net 2009.1.400
.Net Framework v.2.0.50727

currently the report was setup to pull in a "DXF" file.

with

1. Image
Data Column "abc" Command.Drawing

I tried inserting your code there with no success.

we are using and SQL Database w/ Multiple Servers holding information for a given report.

this seems to be my biggest stumbling block

the image location would be as follows in the database

Table = Parts
Colomn = InfoLink1
a path the a JPG file is specified for each individual "Part"

Do I need to create a new Command?

Again - I am NEW to this software - so any Assistance is appreciated

Thank You

Ziggy

How Do I???

Posted: Wed Jan 27, 2010 2:19 pm
by Edward
Hi

Please see attached picture:

If the path is contained in the DataColumn, then this will work:

Thank you.

How Do I???

Posted: Sat Apr 10, 2010 2:01 pm
by Majid000
hi my dear friends ...
i test the below code
but i got this error ... ->

c:\Documents and Settings\Majid\Local Settings\Temp\hw1u-wfy.0.cs(195,30) : error CS0117: 'Stimulsoft.Report.Components.StiImage' does not contain a definition for 'FromFile

i am using stimulreport 2010 ultimate...

How Do I???

Posted: Sun Apr 11, 2010 1:58 pm
by Jan
Hello,

Please use following expression:

Code: Select all

{System.Drawing.Image.FromFile("123.jpeg")}
Thank you.