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SumRunning for group is not working correctly
Posted: Thu Oct 24, 2013 3:37 pm
by LukasT
Hello,
you have no difference between SumRunning for DataBand and for GroupHeader ..... see attached example..... we need this function working that sum will be really for values of group....
Thank you!
Re: SumRunning for group is not working correctly
Posted: Fri Oct 25, 2013 8:25 am
by HighAley
Hello, Lucas.
LukasT wrote:you have no difference between SumRunning for DataBand and for GroupHeader ..... see attached example..... we need this function working that sum will be really for values of group....
We don't see any errors in the attached report.
Could you specify what result are you waiting for?
Thank you
Re: SumRunning for group is not working correctly
Posted: Fri Oct 25, 2013 12:18 pm
by LukasT
Hello, I am expecting that SumRunning for GroupHeader will reset value each new group like Sum function it is doing....
Re: SumRunning for group is not working correctly
Posted: Mon Oct 28, 2013 1:46 pm
by HighAley
Hello.
We need some additional time for analyzing of this issue.
We will let you know about the results.
Thank you.
Re: SumRunning for group is not working correctly
Posted: Mon Nov 11, 2013 7:21 am
by LukasT
Hello,
Any progress, please?
Re: SumRunning for group is not working correctly
Posted: Tue Nov 12, 2013 6:36 am
by HighAley
Hello.
There are some technical difficulties in the implementation of this feature.
It needs some additional time. We will let you know about results.
Thank you.
Re: SumRunning for group is not working correctly
Posted: Fri Dec 06, 2013 11:59 am
by LukasT
Hello,
solution is urgent now.... Should I submit a Ticket, please?
Re: SumRunning for group is not working correctly
Posted: Sat Dec 07, 2013 5:01 am
by Andrew
Hello,
Thank you for the reply.
Yes, please submit a ticket.
Thank you.
Re: SumRunning for group is not working correctly
Posted: Sat Mar 15, 2014 7:54 pm
by Ivan
Hello.
We have made an improvement of the SumRunning algorithm.
The patch will be available in the next prerelease build.
Thank you.