Hi,
I would like to know what performes better,
(a) Creating datasources for each table (like Order and OrderDetails) and Relating them using Data Relation
or
(b) Writing a query by myself (that has all the joins and stuff) to get the same result with out using Data relation of Stimul.
I have a feeling (b) performs better. Any one know the internals of Stimul's Data Relation?
Thanks in advance!!!
Data Relation Performance
Data Relation Performance
StimulReport engine use standard ADO.Net data relations. So you will receive speed equal to any other ADO.Net datarelations from DataSet. If you don't have any troubles with writing one query instead many tables you can use it - this way is more better.raja wrote:Hi,
I would like to know what performes better,
(a) Creating datasources for each table (like Order and OrderDetails) and Relating them using Data Relation
or
(b) Writing a query by myself (that has all the joins and stuff) to get the same result with out using Data relation of Stimul.
I have a feeling (b) performs better. Any one know the internals of Stimul's Data Relation?
Thanks in advance!!!
Thank you.
Data Relation Performance
Thanks for your quick response. So if I understand you correct, option (b) performs better than (a). Let me know if I am wrong. Thanks!!!Vital wrote:StimulReport engine use standard ADO.Net data relations. So you will receive speed equal to any other ADO.Net datarelations from DataSet. If you don't have any troubles with writing one query instead many tables you can use it - this way is more better.raja wrote:Hi,
I would like to know what performes better,
(a) Creating datasources for each table (like Order and OrderDetails) and Relating them using Data Relation
or
(b) Writing a query by myself (that has all the joins and stuff) to get the same result with out using Data relation of Stimul.
I have a feeling (b) performs better. Any one know the internals of Stimul's Data Relation?
Thanks in advance!!!
Thank you.
Data Relation Performance
Yes, option (b) better for perfomance than option (a).
Thank you.
Thank you.